To solve linear equation

PROGRAM :

import java.util.Scanner;

public class LinearEquation {

 

    public static void main(String[] args) {

      

        System.out.println("The linear equation is in the form: aX +bY+c = 0");

        double a,b,c,a1,b1,c1,x,y;

        System.out.println("Enter the value of first linear equation a:");

        Scanner s= new Scanner(System.in);

        a=s.nextDouble();

         System.out.println("Enter the value of first linear equation b:");

        b=s.nextDouble();

         System.out.println("Enter the value of first linear equation c:");

        c=s.nextDouble();

         System.out.println("Enter the value of second linear equation a:");

         a1=s.nextDouble();

         System.out.println("Enter the value of first linear equation b:");

         b1=s.nextDouble();

         System.out.println("Enter the value of second linear equation c:");

         c1=s.nextDouble();

         if(a/a1 != b/b1)

         {

          x= (b*c1 - b1*c)/(a*b1 - a1*b);

          y= (c*a1 - c1*a)/ (a*b1 - a1*b);

          System.out.println("UNIQUE SOLUTION and INTERSECT ALSO");

          System.out.println("values of x : "+x );

          System.out.println("values of y : "+y );

         

         }

         else if (a/a1==b/b1 && b/b1==c/c1)

         {

          System.out.println("infinitely many solutions");

         }

         else if (a/a1==b/b1 && b/b1!=c/c1)

         {

          System.out.println("no solutions");

         }

         

  }

}

OUTPUT :

The linear equation is in the form: aX +bY+c = 0

Enter the value of first linear equation a:

9

Enter the value of first linear equation b:

6

Enter the value of first linear equation c:

3

Enter the value of second linear equation a:

5

Enter the value of first linear equation b:

4

Enter the value of second linear equation c:

9

UNIQUE SOLUTION and INTERSECT ALSO

values of x : 7.0

values of y : -11.0